Which denoted as the constant then put the value of k is divided by 4 Pi Epsilon Not this is the value of Omega so we have the Omega so we can put the value here this time period is equals to 2.Hint: Air pressure is the pressure exerted by the weight of air on the earth’s surface. This is so we can say that that the particle having - futures executing SHM to now latest find the time period for the system for the time period of SHM we can write t is equals to buy under root ke so we can write Omega from here so Mega is equals to omega is equals to 2 under root and K is Is stable equilibrium position sunao per explaining for proving that that its executive the system with no the condition is proportional to minus eggs or f is equals to minus kx this is the first condition aur a must be equal to minus omega square x is added to condition to prove that it is this this particle is executing SHM Sona latest find the force first the electric field in this field anywhere in this sphere is given by easyĢ / RQ argue into our smaller the distance where we want to find the electric field and capital R is the radius of the sphere so Force Force would be equal to buy the cost you know we can find electric field is 4 by 3 Cube is equals to Cuba note after serving this we having a is equals toĬapital Q into 8 / 4 Pi Epsilon not argue this is the this is the so from here we can write F = 2 capital Q into e f is equals to small Kyon into a / 4 5 6 I'm not argue this is a constant is a constant in these all are constant 16 - 10 - you left with the - keep this is minus Q Subah conceive that these are all constant so we can write it as ki The mean position is under root capital to small kid died by 45 points first of all this is this year and this is a charged particle in the sphere is positively charged so the force experienced by the charged particle at the centre is zero and when we did it displays the charged particle by existence it require to regain the position it want to come again on the position of centre of this year so we can say that the centre of the sphere Hello everyone question is positively charged sphere a very thin tunnel has been made along the as shown in figure below a charged particle of minus Q charge of mass M at the end of the tunnel from the situation described mark out the correct statement neglected gravity the statements are charged particle will be performing SHM about the centre of the sphere as mean position time period of the particle is 2.5 under root for eternal mrq / small capital Q particle will perform oscillation but not SHM the speed of the particle will be cross
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